Answer: [tex]1.8409\ kN[/tex]
Explanation:
Given
Mass of student [tex]m=70\ kg[/tex]
Mass of Jupiter [tex]M=1.901\times 10^{27}\ kg[/tex]
Distance between them is [tex]r=6.98\times 10^7\ m[/tex]
Gravitational force is given by
[tex]\Rightarrow F=\dfrac{GmM}{r^2}\\\\\Rightarrow F=\dfrac{6.74\times 10^{-11}\times 70\times 1.901\times 10^{27}}{(6.98\times 10^7)^2}[/tex]
[tex]\Rightarrow F=18.409\times 10^{-11+27-14}=1.8409\ kN[/tex]
If the distance is cut to half, then the force will be four times the initial force
