1066528 1066528
  • 18-03-2021
  • Physics
contestada

Sam moves an 800 N wheelbarrow 5 meters in 15 seconds. How much work did he do?

Respuesta :

dilmtamangs
dilmtamangs dilmtamangs
  • 18-03-2021

Answer:

work done= force × displacement

=800×5

=4000J

Explanation:

The amount of work done is the result of the magnitude of force applied and the displacement of the body due to the force applied. Therefore, work done is defined as the product of the applied force and the displacement of the body.

Answer Link

Otras preguntas

Find the value of W if A=LW, A=8m^2, and L=4m PLEASE HELP
express each as a single power of 2...2^a X 2^b X 2^c2^a+b X 2^a-b
express each as a single power of 2...2^a X 2^b X 2^c2^a+b X 2^a-b
Compare Ponyboy and Cherry Valance
if a triangle has 3 side one is 12 one is 72 what is the last sude
G=H(q+Q)for Q Solve for Q I dont understand how to do this.
what is the KE of a 1 kg ball traveling at 20 meters per second?
A rain barrel is a right circular cylinder. If 1ft^3 =7.5 gallons, how many gallons of rainwater can the barrel hold? Use 3.14 Barrel is 1.35ft left to right..
What is the vertical asymptote for the function f(x) = ln(x + 4) - 2? Be sure to write your answer as an equation for a line.
An automobile engine exerts a force of 595 N to propel the car at 90.0 km/h on a level road.  What is the power output of the engine at that time?