Answer:
[tex]0.55284g/mL[/tex]
Explanation:
Hello there!
In this case, given the by-mass percent of ethanol:
[tex]\frac{70gEt}{100gSol}[/tex]
It is possible to compute the density by using its molar mass to find the grams in one liter of solution:
[tex]12\frac{molEt}{1L}*\frac{46.07 gEt}{1molEt}=552.85g/L[/tex]
However, by taking the g/mL we obtain:
[tex]552.84\frac{g}{L} *\frac{1L}{1000mL}=0.55284g/mL[/tex]
Which is the density of the solution.
Best regards!
