Answer:
The value of p is 1
Step-by-step explanation:
we know that
The standard form of the equation of a horizontal parabola is
(y - k)² = 4p(I - h)
where
(h,k) is the vertex
p[tex]\neq[/tex] 0
if p > 0, the parabola opens to the right, and if p < 0, the parabola opens to the left.
In this problem we have
I = [tex]\frac{1}{4}[/tex]y²
Convert to standard form
y² 4I
The vertex is the point (0,0)
4p = 4
P = 1 -----> p > 0, the parabola opens to the right
