Answer:
220.9g of water are required
Explanation:
The molar enthalpy of vaporization is defined as the heat released when 1 mole of water changes from liquid to gas.
For water, 1 mole releases 40.79kJ. To release 500kJ are necessaries:
500kJ * (1mol / 40.79kJ) = 12.26 moles are necessaries
To convert moles to grams we must use the molar mass (H2O = 18.02g/mol):
12.26 moles * (18.02g / 1 mol) =
220.9g of water are required
