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18-04-2021
Chemistry

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Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Calculate the grams of solute in each of the following solution 278 mL of 0038 M Fe2SO43 class=

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tweelingtom tweelingtom

18-04-2021

Answer:

278 mL x 0.038 M = 10,564 mmol.

Using the molair mass of Fe2(SO4)3 to convert mmol to grams:

10,564 mmol / 1000 x 399,88 g/mol = 4,22 g Fe2(SO4)3.

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