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Answer:
[tex]f^{-1}(x)=\pm\sqrt{x-10}[/tex]
Step-by-step explanation:
You can find the inverse of
y = f(x)
by solving for y:
x = f(y)
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x = y² +10
x -10 = y² . . . . . . . . subtract 10
±√(x -10) = y . . . . . take the square root
The inverse relation is ...
[tex]\boxed{f^{-1}(x)=\pm\sqrt{x-10}}[/tex]
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It is not a function unless some restriction is placed on the domain of f(x).
