Given:
The number [tex]\sqrt{63}[/tex] lies between two whole numbers.
To find:
The two consecutive whole numbers.
Solution:
The perfect squares of natural numbers are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, ... .
The number 63 lies between 49 and 64.
[tex]49<63<64[/tex]
Taking square root on each side, we get
[tex]\sqrt{49}<\sqrt{63}<\sqrt{64}[/tex]
[tex]7<\sqrt{63}<8[/tex]
Therefore, the number [tex]\sqrt{63}[/tex] lies between two whole numbers 7 and 8.
