5= Both parents must both be Heterozygous (Ee) because they have unattached earlobes but can still produce offsprings with attached earlobes because they still possess the recessive gene (e).
6=Punnett Square: (top right)-tt, (bottom right)-tt. Genotypes= Tt, Tt, tt, tt. Phenotypes= Roller(Tt), Roller(Tt), unable to roll(tt), unable to roll(tt).
