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Taking into account the stoichiometry of the reaction, 34.12 grams of LiOH are produced from 9.89 g of Li.

In first place, the balanced reaction is:

2 Li + 2 H₂O ⇒ 2 LiOH + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Li= 2 moles
  • H₂O= 2 moles
  • LiOH= 2 moles
  • H₂= 1 mole

The molar mass of each compound is:

  • Li= 6.94 g/mole
  • H₂O= 18 g/mole
  • LiOH= 23.94 g/mole
  • H₂= 2 g/mole

By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:

  • Li= 2 moles× 6.94 g/mole= 13.88 g
  • H₂O= 2 moles× 18 g/mole= 36 g
  • LiOH= 2 moles× 23.94 g/mole= 47.88 g
  • H₂= 1 mole× 2 g/mole= 2 g

Then you can apply the following rule of three: if by reaction stoichiometry 13.88 g of Li produce 47.88 g of LiOH, 9.89 g of Li produce how much mass of LiOH?

[tex]mass of LiOH=\frac{9.89 g of Li*47.88 g of LiOH}{13.88 f of Li}[/tex]

Solving:

mass of LiOH= 34.12 grams

Finalli, 34.12 grams of LiOH are produced from 9.89 g of Li.

Learn more:

  • https://brainly.com/question/19474065?referrer=searchResults
  • https://brainly.com/question/20703641?referrer=searchResults

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