Respuesta :

ajeigbeibraheem

The molar concentration of Pb+ in a solution that contains 6.73 ppm of Pb(NO3)2 is 2.031 × 10⁻⁵

The molar concentration refers to the molarity of a solution which can be defined as the number of moles of a compound that is present in the solution (usually a 1-liter solution)

Mathematically,

the number of moles = [tex]\mathbf{\dfrac{mass}{molar \ volume }}[/tex]

From the information given:

  • 6.73 ppm (part per million) = 6.3 mg     (since 1 ppm = 1 mg)
  • the mass of 6.73 mg = 0.00673 g

Under standard conditions;

  • the molar mass of Pb(NO3)2 = 331.22 g/mol

∴

The number of moles of Pb(NO3)2 = [tex]\mathbf{\dfrac{0.00673 \ g}{331.22 \ g/mol}}[/tex]

The number of moles of Pb(NO3)2 = 2.031 × 10⁻⁵ mole

Now, the molarity(molar concentration) of the Pb+ in Pb(NO3)2 is:

[tex]\mathbf{=\dfrac{2.305\times 10^{-5}}{1} }[/tex]

= 2.031 × 10⁻⁵

Therefore, we can conclude that the molar concentration of Pb+ in a solution that contains 6.73 ppm of Pb(NO3)2 is 2.031 × 10⁻⁵

Learn more about molarity here:

https://brainly.com/question/15532279?referrer=searchResults

Otras preguntas