[tex]\displaystyle\bf\\3x+2y=4\\-2x+2y=24~\Big|\cdot(-1)\\-----\\3x+2y=4\\2x-2y=-24\\-----------~We~add~up~the~equations\\\\5x~~~~\backslash~~=-20\\\\x=\frac{-20}{5} \\\\\boxed{\bf x=-4}\\\\3x+2y=4\\\\3\cdot(-4)+2y=4\\\\-12+2y=4\\\\2y=4+12\\\\2y= 16\\\\y=\frac{16}{2} \\\\\boxed{\bf y=8}[/tex]
Correct answer: c) (-4, 8)
