Respuesta :
You can use the change of base formula to get
[tex]\log_2(100) = \frac{\log(100)}{\log(2)} \approx 6.643856[/tex]
and also
[tex]\log_6(20) = \frac{\log(20)}{\log(6)} \approx 1.671950[/tex]
In general, the change of base formula is
[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]
Answer:
The value of Log 2 ^ 100 is about 4 times the value of Log 6 ^ 20.
Step-by-step explanation:
trust
