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  • 17-02-2022
  • Chemistry
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what is the oxidation number of boron in Na{B(NO3)4}​

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somestudentx somestudentx
  • 17-02-2022

Answer:

(+3)

Explanation:

The oxidation state of hydrogen in NaBH4 is -1 because here hydrogen acts as a hydride. Thus the oxidation state of boron in sodium boron hydride is (+3)

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