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Calculate the solubility (in g / L) of a generic salt with a formula of A2B, a Ksp of 4.30 × 10−11 and a molar mass of 274 g / mol.

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okpalawalter8

With a Ksp of 4.30*10−11 and a molar mass of 274 g / mol the solubility (in g / L) of the generic salt is mathematically given as

S=0.0604g/l

What is the solubility (in g / L) of the generic salt?

Generally, the Ksp   is mathematically given as

Ksp=4s^3

Therefore

s=(\frac{4.30 × 10−11}{4})^{1/3}

s=2.207×10^{−4]

In conclusion, solubility is

S=2.207×10^{−4]*274

S=0.0604g/l

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