PLEASE HELP!

If 0.00516 mols of HC2H302 are reacted with 0.00585 mols of NaHCO3, which is the limiting reactant?
Show your work.
NaHCO3(s) + HC2H302(aq) → C2H302Na(aq) +H2CO3(aq) H2CO3(aq) - H2O(1) +CO2(g)

Respuesta :

Look at the reaction

More than 1mol of HC2H3O2 is required so the mols will be doubled atleast

  • 0.00516(2)=0.01032mol

Now

NaHCO_3 is less

  • So Sodium bicarbonate is the limiting reagent