The theorem simply states that diagonals of a parallelogram bisect each other is proven as OA = OC.
How to proof the parallelogram?
From the information, OA = OC and OB = OD. In both triangles AOD and BOC, AD = BC since opposite angles are equal.
Also, ADO = CBO since alternate interior angles are equal. Also, DAO = BCO.
Therefore, OA = OC
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