Explanation:
The rule to use here is log(x)-log(y) = log(x/y)
So,
log(6)-log(3) = log(6/3) = log(2)
Answer:
log(2)
Step-by-step explanation:
As we have,
log(a)−log(b)=log(a/b)
Replace 'a' as 6 and 'b' as 3.
Then we get,
[tex]\hookrightarrow log(6)-log(3)\\\\\hookrightarrow log(\frac{6}{3} )\\\\\hookrightarrow log(2)[/tex]
