chuff75 chuff75
  • 20-06-2022
  • Mathematics
contestada

In rhombus ABCD, diagonal BD= 6" and diagonal AC-8".
The sides of the rhombus are

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Medunno13
Medunno13 Medunno13
  • 20-06-2022

Answer: 5

Step-by-step explanation:

Let the point where the diagonals intersect be point E.

Since the diagonals of a rhombus are perpendicular bisectors of each other, this means that:

  • BE = 3
  • AE = 4
  • AEB is a right triangle

So, using the Pythagorean theorem,

[tex]3^{2}+4^{2}=(AB)^{2}\\\\25=(AB)^{2}\\\\AB=5[/tex]

So, each side of the rhombus has a length of 5.

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