vbmaritza83
contestada

A two-digit locker combination is made up of non-zero digits and no digit is repeated in any combination. Event A = the first digit is 4 Event B = the second digit is odd If a combination is chosen at random with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A.5/8
B.4/81
C.1/18
D.5/72

Respuesta :

mathstudent55

Answer:

D. 5/72

Step-by-step explanation:

The non-zero digits are 1 through 9.

There are 9 different non-zero digits.

p(A) = 1/9

There are 5 odd digits.

p(B) = 5/8

p(A and B) = p(A) × p(B) = 1/9 × 5/8 = 5/72

abrily2009

I think the answer is

A: 1/18

Otras preguntas