Respuesta :
The values of 'j' are -11,5.
What is a Quadratic Equation?
- Quadratic equations are the polynomial equations of degree 2 in one variable of the type [tex]f(x) = ax^{2} + bx + c = 0[/tex] where a, b, c, ∈ R and a ≠ 0.
- The standard form of a quadratic equation is [tex]ax^{2} + bx + c = 0[/tex] .
Here, the given equation is (2x+7)(x-5) = - 43 + jx
On simplifying the equation we get,
[tex]2x^{2} -10x+7x-35=-43+jx\\2x^{2} -3x-35+43-jx=0\\2x^{2} -3x-jx+8=0\\2x^{2} -(3+j)x+8=0.....(1)\\[/tex]
By comparing the given equation with the standard form of the quadratic equation we get,
a = 2
b = - (3 + j)
c = 8
Therefore,
[tex](-(3+j))^{2} -4\times2\times8=0\\(3+j)^{2} -64=0\\(3+j)^{2} =64\\[/tex]
Take the square root of both sides,
[tex]\sqrt{(3+j)^{2} }=\sqrt{64} \\[/tex]
3 + j = ±8
Therefore,
3 + j = 8
j = 8 - 3
j = 5
or
3 + j = -8
j = -8 - 3
j = -11
Hence, the possible values of 'j' are -11,5.
Learn more about the quadratic equation at https://brainly.com/question/8649555
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