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An organism is viewed under low power and occupies approximately ¼ of the field diameter. The field diameter of this particular microscope under low power is 2000 µm. Calculate the actual size of the organism.

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The actual size of the organism will be 5 µm.

Microscope magnification

The organism occupies 1/4 of the field diameter.

The field diameter is 2000 µm. So, the organism occupies 1/4 x 2000 = 500 µm.

The total magnification under the low power objective is 100.

100x = 500, x = 500/100 = 5 µm

More on microscope magnification can be found here: https://brainly.com/question/14668612

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