m0chkkbeaniyaaaguer m0chkkbeaniyaaaguer
  • 16-03-2017
  • Chemistry
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What is the ph of a solution of 0.450 m kh2po4, potassium dihydrogen phosphate?

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taskmasters
taskmasters taskmasters
  • 24-03-2017
pKa = -log (Ka) = log [HPO4(2-)] - log[H+]^2 = - log(4.2×10^-13)
pH = - log [H+]
- log [H+]^2 = - 2 log [H+]
2pH = - log (4.2×10^-13) - log [HPO4(2-)]
2pH = - log (4.2×10^-13) - log (0.550)
pH = 6.32

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