syndiebaer
contestada

Quan plans to spend less than $80 for buying groceries. He plans to spend $68.25 on food and spend the rest on juice. Each juice carton costs $3. He is curious how many juice cartons he can purchase before he runs out of money.

ANSWER A and B plz!!!

a) use x to represent the number of juice cartons Quan can purchase and write an inequality that can be used to solve for x.

b) Solve the inequality. Use the solution to determine the number of juice cartons Quan can purchase.

Respuesta :

notbaitable
Y=3X+68.25

80=3X+68.25
Subtract 68.25 from both sides
11.75=3X

Divide

11.75/3=3.91

So he can afford 3 juice cartons
irspow
a)

68.25+3x<80

b)

subtract 68.25 from both sides of the inequality

3x<11.75  divide both sides by 3

x<47/12

Since x must be an integer, the greatest number of cartons that he can purchase is 3.

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