Solve the following equation in the real number system. Please show all of your work. example: x³-6x²-10x+12=0 ... f(x)=x³-6x²-10x+12 A graphing calculator will show that there is one zero at x=-2 Divide f(x) by (x+2) by long division or synthetic division (x³-6x²-10x+12)/(x+2)=x^2-8x+6
solve for other two zeros x^2-8x+6=0 complete the square (x^2-8x+16)+6-16=0 (x-4)^2=10 x-4=±√10 x=4±√10=7.16 and -.84 ans: x=-2, -.84 and 7.16
