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The temperature of a sample of water changes from 10°C to 20°C when the sample absorbs 418 joules of heat. What is the mass of the sample

Respuesta :

mergl
E=(mass)(change in temperature)(specific heat of water)
418=(mass)(20-10)(4.18)
418=(mass)(10)(4.18)
418=(mass)(41.8)
mass=10 grams H2O
pstnonsonjoku

Answer:

0.00995Kg or 9.95g

Explanation:

Mass of the water (m)= ???

Heat capacity of water= 4200JKg-1

Temperature change= 20°C-10°C= 10°C

Heat absorbed =418 J

H=mcø

m= H/cø

m= 418/4200×10

m= 0.00995Kg or 9.95g