angel0741
angel0741 angel0741
  • 20-04-2024
  • Mathematics
contestada

question fifteen
solve
[tex]{x}^{2} + 10x + 21 \geqslant 0[/tex]
​

Respuesta :

georgepahno georgepahno
  • 20-04-2024

Answer:

x² + 10x + 21 ≥ 0

(x + 7)(x + 3) ≥ 0

x ≤ -7 or x ≥ -3

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