ferrariman
ferrariman
16-08-2015
Mathematics
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pleaseeeee helppp!!!!!!!!!!!
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konrad509
konrad509
16-08-2015
[tex]4^{2x}=7^{x-1}\\ 16^x=7^x\cdot7^{-1}\\ \dfrac{16^x}{7^x}=\dfrac{1}{7}\\ \left(\dfrac{16}{7}\right)^x=\dfrac{1}{7}\\ x=\log_{\tfrac{16}{7}}\dfrac{1}{7}\approx-2.35389[/tex]
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