jamesg860 jamesg860
  • 17-10-2017
  • Mathematics
contestada

find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0

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altavistard
altavistard altavistard
  • 17-10-2017
Didn't you mean "Find the possible value or values of z?  y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2).  Thus, the given equation has two equal, real solutions:  z=2 and z=-2.
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