The formula for calculating the distance at constant
velocity is:
d = v * t
d = 15 t
The formula for distance at constant acceleration is:
d = v0 t + 0.5 a t^2
d = 15 t + 0.5 t^2
So after a sum distance of 164 m:
15 t + (15 t + 0.5 t^2) = 164
30 t + 0.5 t^2 = 164
t^2 + 60 t = 328
(t + 30)^2 = 328 + 30^2
t + 30 = ± 35.04
t = -65.04, 5.04
Since time cannot be negative, so the two cars are 164 m
apart after about 5 seconds
