The neutralization reaction would be:
HCl + NaOH --> NaCl + H₂O
Next, determine the equivalent moles of HCl from the given amount of titrant. However, there is a missing information. You should know the molarity of the NaOH to be able to solve this. Suppose, the concentration is 0.1 M NaOH.
0.1 M NaOH * 0.3255 L = 0.03255 mol NaOH
Since, the molar ratio is 1:1, then that is also equivalent to 0.03255 mol HCl. The molarity would then be:
Molarity = 0.03255 mol/0.25 = 0.1302 M HCl
