ItsTayBabyyy ItsTayBabyyy
  • 19-04-2018
  • Chemistry
contestada

What volume of 12.0 M HCL is needed to contain 3.00 moles of HCL

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gabbydpineda gabbydpineda
  • 19-04-2018
solution: 12 M HCL= 3 mol HCL/x
answer: 0.250 L
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