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PLEASE HELP!!! The areas of the squares adjacent to two sides of a right triangle are 29.25^2 units and 13^2 units. Find the length, x, of the third side of the triangle

PLEASE HELP The areas of the squares adjacent to two sides of a right triangle are 29252 units and 132 units Find the length x of the third side of the triangle class=

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Wxlfie

Answer/Step-by-step explanation:

29.25^2 =  855.5625

each length there is 213.89

13^2 = 169

each length here is

42.25

So a^2+b^2 = c^2 (or how i look at it leg^2 + leg^2 = H^2)

42.25^2+213.89^2 = x^2

1785.06+45,748.9321 = x^2

47533.9921 = x^2

then you square eacj side to get x to be alone.

[tex]\sqrt{47533.9921} [/tex]= x

218.02 = x

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